See @spivak1999comprehensive volume 3, page 5.
It is a generalization of Theorema Egregium. Given an immersed Riemannian submanifold in an ambient Riemannian manifold , it provides a relation between the intrinsic curvature of , the extrinsic curvature of and the curvature of . Given the orthogonal complement , we can use the decomposition to define two projections:
with
First, observe the following theorem (@spivak1999comprehensive volume 3, page 2): Theorem 1
Let be an immersion, where is a Riemannian manifold and has the induced metric, and denote by and the covariant derivatives for and , respectively. If , and is a vector field on which is everywhere tangent to , then
where is the usual projection.
On the other hand, notice that
So we can define the tensor field for each , such that for any vector field extending :
where and for we have , for .
Theorem. The tensor is symmetric (Theorem 5 in @spivak1999comprehensive): Proof
Let and be any extensions of to all of which are tangent to at all points of . Then
Let be a hypersurface in , and let be a unit normal field on a neighborhood of in . We define
It turns out that in case of a surface in , this is precisely the second fundamental form. Theorem 8. (@spivak1999comprehensive page 7)
Let be a hypersurface in , and let be a unit normal field on a neighborhood of in .
(a) For all (where is a vector in the tangent space of at ) we have:
(b) If is a vector field tangent along , then we have the Weingarten Equations:
(c) Consequently, we have:
According to this theorem, this second fundamental form is a kind of shape operator, , since for an orthonormal frame in we have:
The Gauss equation plays a crucial role in differential geometry, particularly in the study of surfaces. It relates the intrinsic curvature of a surface to its extrinsic curvature, encapsulating how the surface bends in the ambient space. For an immersed surface , we consider a local orthonormal frame in a neighborhood of a point , is the dual coframe and is the connection 1-form matrix. Gauss equation says that
-Proof of Gauss equation.-
(Also in @needham2021visual section 38.5.1). Consider a point and an open neighborhood of . We have the unit normal vector to the surface , and think of a orthonormal frame defined on such that gives rise to when restricted to . Analogously, we have the dual coframe . We can compute here the connection 1-forms matrix of the standard connection with respect to this frame (see this). It turns out that
where it is satisfied that . To see this, observe that on the one hand we have
and in the other, since is the induced connection by the standard metric in ,
for an arbitrary vector tangent to .
Now, we have to put together several things:
First, we know that Gaussian curvature is the determinant of the shape operator.
Second, it turns out that this determinant can be computed as (see here to see why) evaluated in points of the surface .
Pending task: I want to describe all latter stuff with the method of moving frames. I think I can show that is one of the invariants provided by the MC form, but for the elements of Euclidean group. So is invariant under congruence (like median curvature, I guess). But I don't know yet how to show it for general isometries of the surface. It is maybe explained here. May is also interesting this paper of Chern. (See also @ivey2016cartan page 47)
Maybe this is also related to what is said in Generalization of the flatness of R3.