Gauss' equation

General setup

See @spivak1999comprehensive volume 3, page 5.
It is a generalization of Theorema Egregium. Given an immersed Riemannian submanifold M in an ambient Riemannian manifold N, it provides a relation between the intrinsic curvature of M, the extrinsic curvature of M and the curvature of N. Given the orthogonal complement TpMTpN, we can use the decomposition TpN=TpMTpM to define two projections:

T: TpNTpM(the tangential projection)⊥: TpNTpM(the normal, or perpendicular, projection)

with

X=TX+Xfor all XTpN.

First, observe the following theorem (@spivak1999comprehensive volume 3, page 2):
Theorem 1
Let i:MN be an immersion, where N is a Riemannian manifold and M has the induced metric, and denote by and the covariant derivatives for M and N, respectively. If XpTpM, and Y is a vector field on M which is everywhere tangent to M, then

XpY=T(XpY),

where T:TpNTpM is the usual projection.

On the other hand, notice that

(XfY)=⊥(Xp(f)Yp+f(p)XY)=f(p)(XY).

So we can define the tensor field s:M×MM for each pM, such that for any vector field Y extending Yp:

s(Xp,Yp)=⊥(XY),

where TN=TMM and for VTpN we have V=T(V)(V), for pM.

Theorem. The tensor s is symmetric (Theorem 5 in @spivak1999comprehensive):
Proof
Let X and Y be any extensions of Xp,YpTpM to all of N which are tangent to M at all points of M. Then

(XY)(YX)=⊥(XYpYX)=⊥(XY(p)YX(p))=⊥([X,Y](p))=0,

since [X,Y] is also tangent to M at all points of M.

The tensor s is a kind of second fundamental form, see below.

So we have Gauss' formula:

XpY=XpY+s(Xp,Yp),

and Gauss' equation (generalization of Theorema Egregium):
Theorem 6. Let R and R denote the Riemann curvature tensors of M and N, respectively. For all Xp,Yp,Zp,WpTpM we have:

R(Xp,Yp)Zp,Wp=R(Xp,Yp)Zp,Wp+s(Xp,Zp),s(Yp,Wp)s(Yp,Zp),s(Xp,Wp)

For hypersurfaces

Let M be a hypersurface in N, and let ν be a unit normal field on a neighborhood of p in M. We define

II(Xp,Yp):=ν,s(Xp,Yp).

It turns out that in case of a surface in R3, this is precisely the second fundamental form.
Theorem 8. (@spivak1999comprehensive page 7)
Let M be a hypersurface in N, and let ν be a unit normal field on a neighborhood of p in M.
(a) For all XpTpM (where Xp is a vector in the tangent space of M at p) we have:

XpνTpM.

(b) If Y is a vector field tangent along M, then we have the Weingarten Equations:

Xpν,Yp=ν,XpY=ν,s(Xp,Yp).

(c) Consequently, we have:

Xpν,Yp=Xp,Ypν.


According to this theorem, this second fundamental form II(Xp,) is a kind of shape operator, Xpν, since for an orthonormal frame {ei} in M we have:

II(Xp,ei)=ν,s(Xp,ei)=Xpν,ei.

Closely related, we have the Weingarten map:

XpII(Xp,ei)ei=Xpν,eiei

I think that from here we could define principal curvatures and the extrinsic curvature of the hypersurface...

In case dim(M)=2, we can apply Gauss' equation above to {e1,e2} to obtain:

R(e1,e2)e2,e1=R(e1,e2)e2,e1+s(e1,e2),s(e2,e1)s(e2,e2),s(e1,e1)

Recall that R(e1,e2)e2,e1 is the sectional curvature, so this equation can be rewritten as

Ksect=KKext,

where:

For surfaces in R3

In the case of R3, the sectional curvature is always 0, since the geodesic surfaces are planes. So we have

K=Kext.

Via moving frames

See geometry of a submanifold via moving frames.

Relation with the curvature of the connection

The Gauss equation plays a crucial role in differential geometry, particularly in the study of surfaces. It relates the intrinsic curvature of a surface to its extrinsic curvature, encapsulating how the surface bends in the ambient space. For an immersed surface ι:SR3, we consider a local orthonormal frame {e1,e2} in a neighborhood of a point pS, {ω1,ω2} is the dual coframe and Θ is the connection 1-form matrix. Gauss equation says that

dΘ21=Kω1ω2

(@ivey2016cartan page 47) where K is the Gaussian curvature of the surface.

-Proof of Gauss equation.-
(Also in @needham2021visual section 38.5.1). Consider a point pS and an open neighborhood UR3 of p. We have the unit normal vector to the surface n, and think of a orthonormal frame {e~1,e~2,n~} defined on U such that gives rise to {e1,e2,n} when restricted to S. Analogously, we have the dual coframe {ω~1,ω~2,ζ~}. We can compute here the connection 1-forms matrix Θ~ of the standard connection std with respect to this frame (see this). It turns out that

Θ~=(0Θ~21Θ~31Θ~210Θ¯32Θ¯31Θ¯320)

where it is satisfied that ι(Θ~21)=Θ21. To see this, observe that on the one hand we have

Ve2=VΘ21e1,

and in the other, since is the induced connection by the standard metric in R3,

Ve2=proj((std)Ve~2)=proj(VΘ~21e~1VΘ~32n~)=Vι(Θ~21)e1

for an arbitrary vector V tangent to S.

Now, we have to put together several things:

dΘ~ji=Θ~kiΘ~jk

and then

dΘ~21=Θ~23Θ~31

and

dΘ~21(e1,e2)=Θ~23Θ~31(e1,e2)=Θ~31Θ~23(e1,e2)=Θ~31Θ~32(e1,e2)

If we restrict this identity to S we obtain

dΘ21(e1,e2)=K.

Pending task: I want to describe all latter stuff with the method of moving frames. I think I can show that K is one of the invariants provided by the MC form, but for the elements of Euclidean group E(3). So K is invariant under congruence (like median curvature, I guess). But I don't know yet how to show it for general isometries of the surface. It is maybe explained here. May is also interesting this paper of Chern. (See also @ivey2016cartan page 47)
Maybe this is also related to what is said in Generalization of the flatness of R3.