Maurer-Cartan form on a matrix Lie group

In case G is a matrix Lie group, i.e., GGL(n) then the (left-invariant) Maurer-Cartan form can be computed with the following formula

θ=g1dg

This is the expression appearing everywhere, but I think the correct expression for θ should be, for pG and VTpG

θp(V)=dge1(g(p)1dgp(V))

Pasted image 20220926184710.png

But what is dg? Following @ivey2016cartan definition 1.6.1, g:GMn×n is a parametrization (embedding) of the group as a submanifold of Mn×n but the name g is a bit misleading. For example, consider for SR2 the embedding

ι:SR3

given by ι(a,b)=(a2+b,b,a+b). The differential dι is a map

dι:TSTR3

and we know that for a vector (v1,v2)TpS the image is computed as

dιp(v)=(2a10111)(v1v2)=(2av1+v2v2v1+v2).

If we use the natural identification Tι(p)R3R3 we can think of dι as the R3-valued differential 1-form

dι=(2ada+db,db,da+db)

In the case of g:GMn×n, think in G as the parameter space and Mn×n a fancy way of writing Rn2. So dg is a Mn×n-valued differential form in G. This way, the expression θ=g1dg is also a Mn×n-valued differential form in G.

Examples
I have worked examples in xournal 188 (affine group) and xournal 189 (Euclidean group).

Interpretation

In xournal 189 there is a reflection on how do we understand the Maurer-Cartan form when the group is interpreted as a set of frames. If G is the set of frames or G-descriptions of a homogeneous space X (see this), then for a frame fG, a vector VTfG can be thought as an arrow connecting the frame f with a "nearby" frame f¯, i.e., something like Vf¯fδf. That is, V is a infinitesimal change of the frame p. In this context, θf(V) is nothing but how this infinitesimal change can be described from the own frame f.

The same in other words (following ideas of the end of this): given a frame gG, we can consider a nearby frame g¯g+dg. To express this "frame" in the frame g we take

g1(g+dg)=I+g1dg.

So the Maurer-Cartan form g1dg is the "infinitesimal displacement" of the frame, but described from the point of view of the chosen frame.