Jacobi field

Assume we are in a pseudo-Riemannian manifold.
Let's denote a smooth 1-parameter family of geodesics by γ(t,s), where t is the parameter along each geodesic and s is the parameter that distinguishes different geodesics in the family. We assume that γ(t,s) is twice continuously differentiable with respect to both t and s.

The tangent vector to each geodesic is given by U(t,s)=γt(t,s). Because each curve γ(t,s) is a geodesic, U satisfies the geodesic equation:

DdtU=0,

where Ddt denotes the covariant derivative along a curve for the curve γ(t,s).

Now, consider the variation vector field J(t,s)=γs(t,s). This vector field describes how the geodesics in the family vary with s, and it satisfies the equation:

D2dt2J+R(J,U)U=0,

where Ddt is the covariant derivative along γ(t,0) and R is the Riemann curvature tensor. The expression above is called the Jacobi equation.

Definition
A vector field X defined along a geodesic γ is called a Jacobi field if satisfies Jacobi equation, otherwise written

UUX+R(X,U)U=0


So the variation field of a geodesic variation is a Jacobi field. Here it is shown that any Jacobi field can be realized as the variation field of some geodesic variation of γ.
I.e., there exist a smooth map F:I×(δ,δ)S with

Constant curvature

See @lee2006riemannian lemma 10.8.
Lemma
Suppose (M,g) is a Riemannian manifold with constant sectional curvature C, and γ is a unit speed geodesic in M. The normal Jacobi fields along γ vanishing at t=0 are precisely the vector fields

J(t)=u(t)E(t),

where E is any parallel normal vector field along γ, and u(t) is given by

u(t)={tif C=0;Rsin(tR)if C=R2>0;sinh(1R)if C=R2<0.

Surfaces

In the particular case of a surface, the Riemann curvature tensor satisfies

R(J,U)U=Kg(U,U)JKg(J,U)U

where K is the Gaussian curvature, so if the geodesic is of unit length the Jacobi equation becomes

UUJ+K(Jg(J,U)U)=0,

and if J is normal to U then we have

UUJ+KJ=0.