Gauss' equation

General setup

See @spivak1999comprehensive volume 3, page 5.
It is a generalization of Theorema Egregium. Given an immersed Riemannian submanifold M in an ambient Riemannian manifold N, it provides a relation between the intrinsic curvature of M, the extrinsic curvature of M and the curvature of N. Given the orthogonal complement TpM⊥⊂TpN, we can use the decomposition TpN=TpM⊕TpM⊥ to define two projections:

T: TpN→TpM(the tangential projection)⊥: TpN→TpM⊥(the normal, or perpendicular, projection)

with

X=TX+⊥Xfor all X∈TpN.

First, observe the following theorem (@spivak1999comprehensive volume 3, page 2):
Theorem 1
Let i:M→N be an immersion, where N is a Riemannian manifold and M has the induced metric, and denote by ∇ and ∇′ the covariant derivatives for M and N, respectively. If Xp∈TpM, and Y is a vector field on M which is everywhere tangent to M, then

∇XpY=T(∇Xp′Y),

where T:TpN→TpM is the usual projection.◼

On the other hand, notice that

⊥(∇X′fY)=⊥(Xp(f)⋅Yp+f(p)⋅∇X′Y)=f(p)⋅⊥(∇X′Y).

So we can define the tensor field s:M⊥×M⊥→M⊥ for each p∈M, such that for any vector field Y extending Yp:

s(Xp,Yp)=⊥(∇X′Y),

where TN=TM⊕M⊥ and for V∈TpN we have V=T(V)⊕⊥(V), for p∈M.

Theorem. The tensor s is symmetric (Theorem 5 in @spivak1999comprehensive):
Proof
Let X and Y be any extensions of Xp,Yp∈TpM to all of N which are tangent to M at all points of M. Then

⊥(∇X′Y)−⊥(∇Y′X)=⊥(∇X′Yp−∇Y′X)=⊥(∇X′Y(p)−∇Y′X(p))=⊥([X,Y](p))=0,

since [X,Y] is also tangent to M at all points of M. ◼

The tensor s is a kind of second fundamental form, see below.

So we have Gauss' formula:

∇Xp′Y=∇XpY+s(Xp,Yp),

and Gauss' equation (generalization of Theorema Egregium):
Theorem 6. Let R′ and R denote the Riemann curvature tensors of M and N, respectively. For all Xp,Yp,Zp,Wp∈TpM we have:

⟨R′(Xp,Yp)Zp,Wp⟩=⟨R(Xp,Yp)Zp,Wp⟩+⟨s(Xp,Zp),s(Yp,Wp)⟩−⟨s(Yp,Zp),s(Xp,Wp)⟩

◼

For hypersurfaces

Let M be a hypersurface in N, and let ν be a unit normal field on a neighborhood of p in M. We define

II(Xp,Yp):=⟨ν,s(Xp,Yp)⟩.

It turns out that in case of a surface in R3, this is precisely the second fundamental form.
Theorem 8. (@spivak1999comprehensive page 7)
Let M be a hypersurface in N, and let ν be a unit normal field on a neighborhood of p in M.
(a) For all Xp∈TpM (where Xp is a vector in the tangent space of M at p) we have:

∇Xp′ν∈TpM.

(b) If Y is a vector field tangent along M, then we have the Weingarten Equations:

⟨∇Xp′ν,Yp⟩=−⟨ν,∇Xp′Y⟩=−⟨ν,s(Xp,Yp)⟩.

(c) Consequently, we have:

⟨∇Xp′ν,Yp⟩=⟨Xp,∇Yp′ν⟩.

◼
According to this theorem, this second fundamental form II(Xp,−) is a kind of shape operator, ∇Xp′ν, since for an orthonormal frame {ei} in M we have:

II(Xp,ei)=⟨ν,s(Xp,ei)⟩=−⟨∇Xp′ν,ei⟩.

Closely related, we have the Weingarten map:

Xp↦∑−II(Xp,ei)ei=∑⟨∇Xp′ν,ei⟩ei

I think that from here we could define principal curvatures and the extrinsic curvature of the hypersurface...

In case dim(M)=2, we can apply Gauss' equation above to {e1,e2} to obtain:

⟨R′(e1,e2)e2,e1⟩=⟨R(e1,e2)e2,e1⟩+⟨s(e1,e2),s(e2,e1)⟩−⟨s(e2,e2),s(e1,e1)⟩

Recall that ⟨R(e1,e2)e2,e1⟩ is the sectional curvature, so this equation can be rewritten as

Ksect=K−Kext,

where:

For surfaces in R3

In the case of R3, the sectional curvature is always 0, since the geodesic surfaces are planes. So we have

K=Kext.

Via moving frames

See geometry of a submanifold via moving frames.

Relation with the curvature of the connection

The Gauss equation plays a crucial role in differential geometry, particularly in the study of surfaces. It relates the intrinsic curvature of a surface to its extrinsic curvature, encapsulating how the surface bends in the ambient space. For an immersed surface ι:S→R3, we consider a local orthonormal frame {e1,e2} in a neighborhood of a point p∈S, {ω1,ω2} is the dual coframe and Θ is the connection 1-form matrix. Gauss equation says that

dΘ21=Kω1∧ω2

(@ivey2016cartan page 47) where K is the Gaussian curvature of the surface.

-Proof of Gauss equation.-
(Also in @needham2021visual section 38.5.1). Consider a point p∈S and an open neighborhood U⊂R3 of p. We have the unit normal vector to the surface n, and think of a orthonormal frame {e~1,e~2,n~} defined on U such that gives rise to {e1,e2,n} when restricted to S. Analogously, we have the dual coframe {ω~1,ω~2,ζ~}. We can compute here the connection 1-forms matrix Θ~ of the standard connection ∇std with respect to this frame (see this). It turns out that

Θ~=(0Θ~21Θ~31−Θ~210Θ¯32−Θ¯31−Θ¯320)

where it is satisfied that ι∗(Θ~21)=Θ21. To see this, observe that on the one hand we have

∇Ve2=V⌟Θ21e1,

and in the other, since ∇ is the induced connection by the standard metric in R3,

∇Ve2=proj((∇std)Ve~2)=proj(V⌟Θ~21e~1−V⌟Θ~32n~)=V⌟ι∗(Θ~21)e1

for an arbitrary vector V tangent to S.

Now, we have to put together several things:

dΘ~ji=−Θ~ki∧Θ~jk

and then

dΘ~21=Θ~23∧Θ~31

and

dΘ~21(e1,e2)=Θ~23∧Θ~31(e1,e2)=−Θ~31∧Θ~23(e1,e2)=Θ~31∧Θ~32(e1,e2)

If we restrict this identity to S we obtain

dΘ21(e1,e2)=K.

Pending task: I want to describe all latter stuff with the method of moving frames. I think I can show that K is one of the invariants provided by the MC form, but for the elements of Euclidean group E(3). So K is invariant under congruence (like median curvature, I guess). But I don't know yet how to show it for general isometries of the surface. It is maybe explained here. May is also interesting this paper of Chern. (See also @ivey2016cartan page 47)
Maybe this is also related to what is said in Generalization of the flatness of R3.